-16t^2+60t+3=3(t)

Solution for -16t^2+60t+3=3(t) equation:

-16t^2+60t+3=3(t)

We move all terms to the left:

-16t^2+60t+3-(3(t))=0

determiningTheFunctionDomain
-16t^2+60t-3t+3=0

We add all the numbers together, and all the variables

-16t^2+57t+3=0

a = -16; b = 57; c = +3;
Δ = b2-4ac
Δ = 572-4·(-16)·3
Δ = 3441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-\sqrt{3441}}{2*-16}=\frac{-57-\sqrt{3441}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+\sqrt{3441}}{2*-16}=\frac{-57+\sqrt{3441}}{-32}
$